Witryna16 mar 2024 · Ex 7.4, 5 3𝑥/ (1 + 2𝑥4) Let 𝑥^2=𝑡 Differentiating both sides 2𝑥=𝑑𝑡/𝑑𝑥 𝑑𝑥=𝑑𝑡/2𝑥 Integrating the function 𝑤.𝑟.𝑡.𝑥 ∫1 (3𝑥 )/ (1 + 2𝑥^4 ) 𝑑𝑥 =∫1 3𝑥/ (1 + 2 (𝑥^2 )^2 ) 𝑑𝑥 Putting value of 𝑥^2=𝑡 and 𝑑𝑥=𝑑𝑡/2𝑥 =∫1 3𝑥/ (1 + 2𝑡^2 ) 𝑑𝑥 =∫ ... Witrynaedited Mar 13, 2013 at 21:56. answered Mar 13, 2013 at 21:50. André Nicolas. 498k …

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WitrynaCalculus Evaluate the Integral integral of 1/ (3x-1) with respect to xdx ∫ 1 3x − 1 dxdx ∫ 1 3 x - 1 d x d x Let u = 3x−1 u = 3 x - 1. Then du = 3dx d u = 3 d x, so 1 3du = dx 1 3 d u = d x. Rewrite using u u and d d u u. Tap for more steps... ∫ 1 u ⋅ 1 3dudx ∫ 1 u ⋅ 1 3 d u d x Simplify. Tap for more steps... ∫ 1 3ududx ∫ 1 3 u d u d x Witryna1.2K views 1 year ago Integration - Logarithmic Rule and Exponentials. Evaluate the … bitwise controls

7.4E: Exercises for Integration by Partial Fractions

WitrynaThe value of ∫ 8+3x−x 2dx is equal to A 32sin −1( 412x−3)+C B 23sin −1( 412x−3)+C C 411 sin −1( 412x−3)+C D sin −1( 412x−3)+C Hard Solution Verified by Toppr Correct option is D) Let l=∫ 8+3x−x 2dx dx =∫ −[x 2−3x+(23)2−(23)2]+81 dx =∫ 8+ 49−(x− 23)2dx =∫ ( 2 41)2−(x− 23)2dx =sin −1⎝⎜⎜⎜⎛ 2 41x− 23⎠⎟⎟⎟⎞+C=sin −1( 412x−3)+C. … WitrynaIndefinite Integration - Geometrical Meaning. 10 mins. Shortcuts & Tips . Mindmap > … WitrynaEvaluate the Integral integral of 1/ (1-3x) with respect to xdx ∫ 1 1 − 3x dxdx ∫ 1 1 - 3 x d x d x Let u = 1−3x u = 1 - 3 x. Then du = −3dx d u = - 3 d x, so −1 3du = dx - 1 3 d u = d x. Rewrite using u u and d d u u. Tap for more steps... ∫ 1 u ⋅ 1 −3 dudx ∫ 1 u ⋅ 1 - 3 d u d x Simplify. Tap for more steps... ∫ − 1 3ududx ∫ - 1 3 u d u d x date as of today